The number 3 is here, as I said, so you would be able to give color to the new histogram.
This can be achieved in the following manner: newZ=zeros(size(Z),3) You can achieve that by creating a zero matrix with the same size as Z, but having in mind that in order to be in color, it has to have an additional dimension, which will specify the three color components (if you are working with RGB).
#Hist3 matlab 2014a code#
745 and maxZ), you can write the following code so you can create the newZ.įirst you need to specify that newZ is of the same size as Z. Then you can calculate the number of overlaping values in this manner: if 745 > maxZĪt this point you have 10 overlapping values (or more if you still think that it doesn't looks good) if the maximum value of the Z is bigger than the total amount of values you are trying to assign to the new Z, or overlap overlapping values, if the maximum of Z is smaller.
If 745 > maxZ there is no logic for you to map the new Z with more than maxZ values. So, if you decide that you will have, for example overlapping of 10 values, than, having in mind that every R, G and B component of the RGB color images have 255 values (8 bits) and 10 of each overlap with the former, that means that you will have 255 values (from the Blue) + 245 values (From the Green, which is 255 - 10 since 10 of the Green overlap with those of the Blue) + 245 (From the Red, with the same comment as for the Green), which is total amount of 745 values that you can assign to the new colored Histogram. For example, if you use RGB system and you assign Blue for the lowest values of the histogram, then Green for the middle and Red for the High, and the green starts after the Blue with no overlap, than it will look artificial.
Then, you need to calculate how much of the colors should overlap. To do that, you need to first calculate the maximum Z value with: maxZ=max(Z) I haven't tried using colormap on histograms directly, so If colormap doesn't help, then you can try creating a new matrix manually which will have values in colors instead of the Z values the histogram originally had. If that's not what you need, you might wanna try it with colormap. set(get(gca,'child'),'FaceColor','interp','CDataMode','auto') The hist3 documentation, which you can find here hist3, says:Ĭolor the bars based on the frequency of the observations, i.e.
#Hist3 matlab 2014a how to#
I don't know what the colour is being produced based on.Īdditionally, if possible, I would also like to know how to plot the hist3 on a 3D map of the world (or globe), where each bar of the hist3 would correspond to the frequency of each location (i.e., each latitude-longitude pair). Geoshow(geoid, geoidrefvec, 'DisplayType', 'texturemap') How to do this? I could only plot the skeleton of the worldmap like this: worldmap world I have been searching a lot for this, but have not found much help. And instead of representing the frequency of each latitude-longitude pair with the height of the bars of hist3, I want to represent the frequency of each location by a heat map on top of the world map, corresponding to each latitude-longitude pair's frequency on the dataset. What I now want is, instead of plotting on a self-created XY plane, I want to plot the same on a worldmap. It is given by: z=hist3(location(:,1:2),), where location(:,1) is the latitude column, and location(:,2) is the longitude column. My x-axis is latitudes, y-axis is longitudes, and z-axis is the hist3 of the two.
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